tolomg bantu ya,isi make caranya. makasih

jawab

f(x) = (2x+1)/(x-3)

f⁻¹ { (2x+1)/(x-3)} = x

y = (2x +1)/(x-3)
y(x - 3) = 2x + 1
xy - 3y = 2x + 1
xy -2x = 3y  + 1
x (y -2) = (3y +1)
x = (3y +1)/(y-2)
f⁻¹ (y) = (3y +1)/(y -2)

f⁻¹ (x) = (3x + 1)/(x - 2)
f⁻¹ (x+1) = { 3(x+1) +1 } / (x +1 - 2)
f⁻¹ (x+1) = (3x + 3 + 1)/ (x - 1)
f⁻¹ (x+1) = (3x + 4)/(x -1)

Ikutan..

f(x) = y = (2x + 1)/(x - 3)
y(x - 3) = 2x + 1
xy - 3y = 2x + 1
xy - 2x = 3y + 1
x(y - 2) = 3y + 1
x = (3y + 1)/(y - 2)

f^-1 (x) = (3x + 1)/(x - 2)

f^-1 (x + 1)
= (3(x + 1) + 1) / (x + 1 - 2)
= (3x + 4) / (x - 1) ✔

Opsi : D