koordinat titik balik grafik fungsi kuadrat y=-x2 - 8x + 2
Matematika
elvyasitepu15
Pertanyaan
koordinat titik balik grafik fungsi kuadrat y=-x2 - 8x + 2
1 Jawaban
-
1. Jawaban Anonyme
Bab Fungsi Kuadrat
Matematika SMP Kelas VIII
f(x) = -x² - 8x + 2
a = -1; b = -8; c = 2
sumbu simetri = x
= -b/2a
= -(-8)/(2 . -1)
= -4
f(-4) = -(-4)² - 8 . (-4) + 2
f(-4) = -16 + 32 + 4
f(-4) = 20
koordinat titik balik = (-4, 20)