di ketahui tan x = -24/10 dan cos y= 3/5. jika x di kuadran II dan y di kuadran IV, tentukan : b. sin (x+y) c. tan (x+y)/tan (x-y) pls di bantu dengan benar ya:

Sin x=24/26
Cos x=-10/26
Sin y=-4/5
Tan y=-4/3
Sin (x+y) =sin x cos y+cos x sin y
=24/26.3/5+(-10/26.-4/5)
=72/130 + 40/130
=112/130=56/65
Tan(x+y) / tan (x-y)
=tan x+tan y/(1-tan x tan y) : tan x-tan y/(1+tan x tan y)
=-24/10+(-4/3)/1-(-24/10)(-4/3) : -24/10-(-4/3)/1+(-24/10)(-4/3)
=-112/30 /1-96/30 : -32/30 /1+96/30
=-112/30.(-30/66) : -32/30.30/126
=112/66 : -32/126
=112/66.-126/32
=-7.21/11.2
=-147/22