2 buah dadu dilempar bersama sama .tentukan peluang a. Muncul mata dadu kedua bermata 3 b. Muncul kedua dadu bernomor sama c. Muncul mata dadu pertama lebih bes

n(S) = 6² = 36

a) n(P) = (1,3)(2,3)(3,3)(4,3)(5,3)(6,3) = 6
peluang = 6/36 = ¹/6

b) n(P) = (1,1)(2,2)(3,3)(4,4),(5,5)(6,6) = 6
peluang = 6/36 = 1/6

c) n(p) = (2,1)(3,1)(4,1)(5,1)(6,1)(3,2)(4,2)(5,2)(6,2)(4,3)(5,3)(6,3)(5,4)(6,4)(6,5) = 15
peluang = 15/36