Garis h melalui titik 2,-1 dan tegak luris garis g. Diketahui garis g :6x-4y-9=. tentukan pers garis h

6x - 4y - 9 = 0
- 4y = - 6x + 9
y = 6/4 x - 9/4
m = 6/4

syarat tegak lurus
m1 . m2 = - 1
6/4 . m2 = - 1
m2 = - 1 ÷ 6/4
m2 = - 4/6

garis h
y - y1 = m (x - x1)
y + 1 = - 4/6 (x - 2)
y + 1 = - 4/6 x + 4/3
y = - 4/6x + 4/3 - 1
y = - 4/6x + ⅓
---------------------(×6)
6y + 4x - 2 = 0