²Log2 + ²Log3 - ²Log6 - ²Log8 =
Matematika
arums762
Pertanyaan
²Log2 + ²Log3 - ²Log6 - ²Log8 =
2 Jawaban
-
1. Jawaban subebe
2log2 + 2log3 - 2log6 - 2log8
= 2log (2 x 3 /(6x8))
= 2log 1/8
= 2log 2^-3
= -3 x 2log2
= -3 x 1
= -3 -
2. Jawaban evanpaembonan11
=²log 2×3 - ²log 6/8
=²log6-²log3/4
=²log 6 : 3/4
=²log8
=²log2³
=3
jadi hasilx adalah 3