Matematika

Pertanyaan

integral (√x²-4)/x dx =

1 Jawaban

  • integral V(x^2 -4) x dx
    = integral ( x^2 - 4)^1/2 x dx
    misal : U = x^2 - 4
    du/dx = 2x
    dx = du/2x
    integral u^1/2 x du/2x
    = 1/2 integral u^1/2 di
    = 1/2 u^3/2 / (3/2) + c
    = 1/3 u^3/2 + c
    = 1/3(x^2 - 4) V(x^2 - 4) + c

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