integral (√x²-4)/x dx =
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Pertanyaan
integral (√x²-4)/x dx =
1 Jawaban
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1. Jawaban nasril8
integral V(x^2 -4) x dx
= integral ( x^2 - 4)^1/2 x dx
misal : U = x^2 - 4
du/dx = 2x
dx = du/2x
integral u^1/2 x du/2x
= 1/2 integral u^1/2 di
= 1/2 u^3/2 / (3/2) + c
= 1/3 u^3/2 + c
= 1/3(x^2 - 4) V(x^2 - 4) + c