dua buah dadu di tos sebanyak 1 kali.tentukan peluang muncul mata dadu; a.berjumlah genap b.berjumlah bilangan genap c.berjumlah kurang dari 6 d.mata dadu prima

A. 18/36 = 1/2
B. 9/36 = 1/4
C. 10/36 = 5/18
D. Kurang mengerti maksud dari soal

Maaf kalau salah

n (S) = 36

a.) n (A) = {(1,1), (1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3), (3,5), (4,2), (4,4), (4,6), (5,1),(5,3), (5,5), (6,2), (6,4), (6,6)} = 18

Peluang = n (A) / n (S)
Peluang = 18/36 = 1/2

b.) n (A) = {(1,1), (1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3), (3,5), (4,2), (4,4), (4,6), (5,1),(5,3), (5,5), (6,2), (6,4), (6,6)} = 18

Peluang = n (A) / n (S)
Peluang = 18/36 = 1/2

c.) n (A) = {(1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1)} = 10

Peluang = n (A) / n (S)
Peluang = 10/36 = 5/18

d.) n (A) = {(2,2), (2,4), (2,6), (3,2), (3,4), (3,6), (5,2), (5,4), (5,6)} = 9

Peluang = n (A) / n (S)
Peluang = 9/36 = 1/4

Semoga membantu dan semoga bermanfaat...