tentukan Hp persamaan kuadrat 4x²-8x+4=0 rumus abcd
Matematika
AlColz12
Pertanyaan
tentukan Hp persamaan kuadrat 4x²-8x+4=0 rumus abcd
2 Jawaban
-
1. Jawaban Anonyme
Persamaan Kuadrat
4x² - 8x + 4 = 0
4(x² - 2x + 1) = 0
x² - 2x + 1 = 0
a = 1
b = -2
c = 1
Rumus abc (gk pake d :) ) :
x1.2 = (-b ± √(b² - 4ac))/2a
x1.2 = (2 ± √(4 -4))/2
x1.2 = 2/2
x1.2 = 1
Akar2 nya kembar :
x1 = x2 = 1
HP = {1} -
2. Jawaban 01ABC
4x²-8x+4=0 => dibagi 4
4 (x² - 2x + 1) = 0
4 (x - 1)(x - 1) = 0
4 (x - 1)² = 0
Himpunan
x - 1 = 0
x = 1