Matematika

Pertanyaan

tentukan Hp persamaan kuadrat 4x²-8x+4=0 rumus abcd

2 Jawaban

  • Persamaan Kuadrat

    4x² - 8x + 4 = 0
    4(x² - 2x + 1) = 0
    x² - 2x + 1 = 0
    a = 1
    b = -2
    c = 1

    Rumus abc (gk pake d :) ) :
    x1.2 = (-b ± √(b² - 4ac))/2a
    x1.2 = (2 ± √(4 -4))/2
    x1.2 = 2/2
    x1.2 = 1

    Akar2 nya kembar :
    x1 = x2 = 1

    HP = {1}
  • 4x²-8x+4=0 => dibagi 4
    4 (x² - 2x + 1) = 0
    4 (x - 1)(x - 1) = 0
    4 (x - 1)² = 0

    Himpunan
    x - 1 = 0
    x = 1

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