tentukan garis garis lurus yang melaluititik a (2,1 ) dan b (3,6 )

y = mx + c
cari m
m = 6 - 1/ 3 -2 = 5
y - y1 = m (x - x1) + y1
y - 1 = 5 (x - 2) + 1
y = 5x - 10 + 2
y= 5x - 8

(y-y1)/(y2-y1)=(x-x1)/(x2-x1)
<=> (y-1)/(6-1)=(x-2)/(3-2)
<=> (y-1)/(5)=(x-2)/(1)
<=> 1(y-1)=5(x-2)
<=> y-1=5x-10
<=> y=5x-10+1
<=> y=5x-9