Matematika

Pertanyaan

Tentukan HP dari setiap persamaan berikut
a.2log x+ 2log (x-2)=3
b.log (x-2)+log (x-1)=log 6
c.log (2x-1)-log (x-3)=log 7

1 Jawaban

  • ²logx + ²log(x-2) = 3
    ²log(x(x-2)) = ²log2³
    ⇔ x(x-2) = 2³
    ⇔ x² - 2x - 8 = 0
    ⇔ (x + 2)(x - 4) = 0
    ⇔ x = -2  atau  x = 4
    HP : {-2, 4}


    log (x-2)+log (x-1)=log 6
    log((x-2)(x-1)) = log6
    ⇔ (x-2)(x-1) = 6
    ⇔ x² - 3x +2 - 6 = 0
    ⇔ x² - 3x - 4 = 0
    ⇔ (x + 1)(x - 4) = 0
    ⇔ x = -1   atau   x = 4
    HP : {-1, 4}



    log (2x-1)-log (x-3)=log 7
    log(
    (2x-1)/(x-3)) = 7
    ⇔ (2x-1)/(x-3) = 7
    ⇔ 2x - 1 = 7x - 21
    ⇔ 5x - 20 = 0
    ⇔ 5x = 20
    ⇔ x = 4

    HP : {4}

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