Diketahui f(x)=ax+b jika f(2)=4 fdan f(5)=13 maka nilai f(10) adalah
Matematika
vanifirmansyah
Pertanyaan
Diketahui f(x)=ax+b jika f(2)=4 fdan f(5)=13 maka nilai f(10) adalah
2 Jawaban
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1. Jawaban BSunShine
Fungsi
f(x) = ax + b
f(2) = a2 + b
f(2) = 2a + b
4 = 2a + b
f(5) = a5 + b
f(5) = 5a + b
13 = 5a + b
2a + b = 4
5a + b = 13
---------------- [-]
-3a = -9
a = 3
2a + b = 4
2(3) + b = 4
6 + b = 4
b = 4 - 6
b = -2
f(x) = 3x + (-2)
f(x) = 3x - 2
f(10) = 3(10) - 2
f(10) = 30 - 2
f(10) = 28
*Thanks -
2. Jawaban NicodiAngelo
f(x) = ax + b
f(2) = a(2) + b
4 = 2a + b
f(5) = a(5) + b
13 = 5a + b
13 = 5a + b
4 = 2a + b
----------------- -
9 = 3a
a = 3
f(2) = 3(2) + b
4 = 6 + b
b = (-2)
f(10) = 3(10) -2
= 30 - 2
= 28