jika tan α = √2 dan a sinα = √6/9 α sudut lancip maka nilai a haruslah

TriGonoMetRi

tan x = y/x = √2 /1
r = √(y² + x²)
r = √((√2)² + 1²)
r = √3

a sin x = √6 /9
a . y/r = √6 /9
a . √2 /√3 = √2 . √3 /9
a = √3 . √3 /9
a = 3/9
a = 1/3 ✔