Tolong kasi tau caranyaa

f(x) = 2x - 1, g (x ) = x^2 + 2, dan h(x,) = 1/ (x-1)
gohof(x)
= g { h ( f(x) ) }
= g.{ h ( 2x - 1) }
= g { 1/( 2x - 1) - 1 )
= g ( 1/(2x -2 ) }
= { 1/(2x -2) }^2 + 2
= 1 / (2x - 2)^2 + 2
= { 1 +2(2x - 2)^2 } / (2x - 2)^2
= ( 1 + 8x^2 -16x +8) / (2x-2)^2
= (8x^2 - 16x + 9) / (2x-2)^2