QUIZZ!!! NO COPY!! DENGAN CARA!! HARUS DIJAWAB SEMUANYA!! 1.Hasil dari log 25+ log 5 + log 80 ialah? 2.Jika diketahui log x=0,845,maka nilai x adalah? 3.Tentuka

1.) log 25 + log 5 + log 80
= log (25 x 5 x 80)
= log 10000
= 4

2.) log x = 0,845
x = [tex] 10^{0,845} [/tex]
x ≈ 6,998

3.) ⁴log 8 + ²⁷log 9
= [tex] ^{2^{2}} \log 2^3 + ^{3^{3}} \log 3^2 [/tex]
= 3/2 • ²log 2 + 2/3 • ³log 3
= 3/2 + 2/3
= 13/6

4.)
a. [tex] ^{\sqrt{2}} \log 8 [/tex]
=[tex] ^{2^{1/2}} \log 2^3 [/tex]
= 3 • 2 • ²log 2
= 6

b. [tex] ^{\sqrt{3}} \log 27 [/tex]
= [tex] ^{3^{1/2}} \log 3^3 [/tex]
= 3 • 2 • ³log 3
= 6

5.)
²log 7 = a
²log 3 = b

Maka
⁶log 14 = ²log 14 / ²log 6
= (²log 7 • 2) / (²log 3 • 2)
= (²log 7 + ²log 2) / (²log 3 + ²log 2)
= (a + 1) / (b + 1)

NO 1
[tex]=\log { 25 } +\log { 5 } +\log { 80 } \\ =\log { (25\cdot 5\cdot 80) } \\ =\log { ({ 5 }^{ 3 }\cdot 10\cdot { 2 }^{ 3 }) } \\ =\log { ({ 10 }^{ 3 }\cdot 10) } \\ =\log { { 10 }^{ 4 } } \\ =4[/tex]
NO 2
[tex]\log { x } =0,845\\ \log { x } =\frac { 845 }{ 1000 } \\ \log { x } =\frac { 169 }{ 200 } \\ \Longleftrightarrow x={ 10 }^{ \frac { 169 }{ 200 } }[/tex]
NO 3
[tex]=\log _{ 4 }{ 8 } +\log _{ 27 }{ 9 } \\ =\log _{ { 2 }^{ 2 } }{ { 2 }^{ 3 }+\log _{ { 3 }^{ 3 } }{ { 3 }^{ 2 } } } \\ =\frac { 3 }{ 2 } +\frac { 2 }{ 3 } \\ =1\frac { 1 }{ 2 } +\frac { 2 }{ 3 } \\ =1+\frac { 3+4 }{ 6 } \\ =2\frac { 1 }{ 6 } [/tex]
NO 4
ROM A
[tex]=\log _{ \sqrt { 2 } }{ 8 } \\ =\log _{ { 2 }^{ \frac { 1 }{ 2 } } }{ { 2 }^{ 3 } } \\ =\frac { 3 }{ \frac { 1 }{ 2 } } \\ =6[/tex]
ROM B
[tex]=\log _{ \sqrt { 3 } }{ 27 } \\ =\log _{ { 3 }^{ \frac { 1 }{ 2 } } }{ { 3 }^{ 3 } } \\ =\frac { 3 }{ \frac { 1 }{ 2 } } \\ =6[/tex]
[tex]=\log _{ 6 }{ 14 } \\ =\frac { \log _{ 2 }{ 14 } }{ \log _{ 2 }{ 6 } } \\ =\frac { \log _{ 2 }{ (7\times 2) } }{ \log _{ 2 }{ (3\times 2) } } \\ =\frac { \log _{ 2 }{ 7 } +\log _{ 2 }{ 2 } }{ \log _{ 2 }{ 3 } +\log _{ 2 }{ 2 } } \\ =\frac { a+1 }{ b+1 } [/tex]NO 5