gambar menunjukkkan 2 tabung yg mmiliki volume yg sama. jika perbandingan jari jari r1:r2=2:1,maka perbandingan t1:t2 adalah…

v1 : v2 = π × r² × t : π × r² × t
π × (2)² × t1 : π × (1)² × t2
4t1 : t2
jadi t1 : t2 = 4 : 1

r1 : r2 = 2 : 1
r1 = 2x
r2 = x

V1 = V2
π r1² t1 = π r2² t2
r1² t1 = r2² t2
(2x)² t1 = x² t2
4x² t1 = x² t2
4 t1 = t2
t1/t2 = 1/4
t1 : t2 = 1 : 4