Matematika

Pertanyaan

Jika p = cscx nilai dari cot²x + sin²x + cos² - 2cscx =

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2 Jawaban

  • sin²x+cos²x=1
    cot²x+1-2p= 1/tan²x+1-2p
    1/tanx . 1/tanx +1-2p
    cosx/sinx . cosx/sinx+1-2p
    cosx . 1/sinx. cosx . 1/sinx +1-2p
    cosx.p.cosx.p+1-2p
    p²cos²x+1-2p
  • TriGonoMetRi

    csc x = p
    1/sin x = p
    sin x = 1/p

    cos² x = (1 - sin² x)
    cos² x = 1 - 1/p²
    cos² x = (p² - 1)/p²

    ••
    cot² x + (sin² x + cos² x) - 2 csc x
    = cos² x/sin² x + 1 - 2 csc x
    = (p² - 1) + 1 - 2p
    = p² - 2p ✔

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