cara persamaan garis melalui titik (2,-3) sejajar garis 3y + 6x =10
Matematika
triana68
Pertanyaan
cara persamaan garis melalui titik (2,-3) sejajar garis 3y + 6x =10
1 Jawaban
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1. Jawaban Anonyme
Persamaan Garis Lurus.
ax + by + c = 0
6x + 3y - 10 = 0
Persamaan garis melalui titik (2, -3) sejajar garis 3y + 6x = 10 adalah:
ax + by = ax₁ + by₁
6x + 3y = 6(2) + 3(-3)
6x + 3y = 3
2x + y - 1 = 0