persamaa garis melalui titik (2,-3)sejajar garis -3y+6x=10

diket : x1= 2 y1= -3 sejajar dgn garis -3y+6x=10
dit. : per.garis...?
jwb:
-3y+6x=10
m= -x/y= -6/-3=2
m1=m2= 2
Per.garis
y-y1= m(x-x1)
y-(-3)= 2(x-2)
y+3= 2(x-2)
y+3= 2x-4
y = 2x-4-3
y = 2x-7 (1)
2x-y-7=0 (2)
2x-y = 7 (3)

Bab Persamaan Garis
Matematika SMP Kelas VIII

ax + by = c, sejajar, (p, q)
ax + by = ap + bq

6x - 3y = 10, sejajar, (2, -3)
6x - 3y = 6 . 2 - 3 . (-3)
6x - 3y = 12 + 9
6x - 3y = 21
2x - y = 7