Matematika

Pertanyaan

x-6 per x-3 >= x-2 per x+1

1 Jawaban

  • [tex] \frac{x-6}{x-3} [/tex] ≥ [tex] \frac{x-2}{x+1} [/tex]
    (x-6)(x+1) ≥ (x-2)(x-3)
    x²-5x-6 ≥ x²-5x+6
    -6 ≥ 6


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