x-6 per x-3 >= x-2 per x+1
Matematika
jiwamata
Pertanyaan
x-6 per x-3 >= x-2 per x+1
1 Jawaban
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1. Jawaban juliettasiahaan
[tex] \frac{x-6}{x-3} [/tex] ≥ [tex] \frac{x-2}{x+1} [/tex]
(x-6)(x+1) ≥ (x-2)(x-3)
x²-5x-6 ≥ x²-5x+6
-6 ≥ 6