Tolong yang bisa No 5 Dan No 7

jawab
Mo = 162
Tb = 159,5
c = 10
d1 = x- 8
d2 = x - 2

Mo =  tb +  (c. d1)/(d1+d2)
162 = 159,5 + 10(x-8) /(x-8+x -2)
162 - 159,5 = 10(x-8)/(2x -10)
2, 5 =  (10 x- 80) / (2x -10)
10x - 80 =  2,5(2x -10)
10x - 80 =  5x  - 25
5x  = 80-25 = 55
x = 11

Mean 
X = [ 3(144,5) + 8(154,5) + 11(164,5) + 2(174,5)] / (3+8+11+2)
X = (3828)/(24)
X= 159,5


(7)
Qi  = tb + c(i/4 . fi)/(fq)
q1 = 149,5 + 10(6-3)/8= 153,25
q2 = 159,5 +10(12-11)/(11) = 160,41
q3 = 159,5+10(18-11)/(11) = 165,86