a father is three times as old as his daughter. the difference in their age is 32. find the sum of their ages in 10 year's time.

3 : 1
diference
= 32 = 3-1
= 32 = 2

1 unit = 32 ÷ 2 = 16

So, now = 3 × 16 : 1 × 16 = 48 : 16

10 years again = 48 + 10 : 16 + 10 = 58:26
Sum = 58 + 26 = 84