sebuah taman persegi panjang berukuran panjang (3x-4) meter dan lebar (x+2) meter. jika keliling taman 36 meter, luad taman itu adalah...

k = 2 × (3x - 4)+(x + 2)
36 = 2 × (4x - 2)
36 = 8x - 4
36 + 4 = 8x
x = 40 ÷ 8 = 5
p = 3(5) - 4 = 11
l = 5 + 2 = 7
L = 11 × 7 = 77

K. persegi panjang =2[p+l}
36 meter. =2[(3x-4)+(x+2)]
36 meter. =2 x (4x-2)
36. =8x-4
36+4 =8x
40 =8 x
x=40÷8
=5

p=3x-4
=3.5-4
=11
l=x+2
=5+2
=7

luas = pxl
=11x7
=77 cm²