nilai (x,y) yang memenuhi sistem persamaan 2x-3y=12 , 3x+4y=1 adalah...

2x - 3y = 12 (x 3)
3x + 4y = 1 (x 2) /

-9y = 36
-8y = 2 (-)

-y = 34.

2x - 3y = 12
2x - 3(34) = 12
2x - 102 = 12
2x = 114
x = 114 : 2 = 57.

Jadi nilai x = 57, nilai y = 34.