Diketahui ²log 3=a dan ² log 5=b, nilai 9 log 150

2^log 3 = a; 2^log 5 = b
9^log 150 = 2^log 150/ 2^log 9
= (2^log 5^2 + 2^log 2 + 2^log3) / 2^log 3^2
= (2 x 2^log5 + 1 + 2^log 3) / 2 x 2^log3
= (2b + 1+ a) / 2a