Jika sinA = 5/13 dan cosB = 7/25 ,dimana A dan B lancip , maka Tan(A+B) =.... Mohon bantuannya yaa terima kasih

sin A = 5/13 maka tan A= 5/12
cos B = 7/25 maka tan B = 24/7
tan (A+B) = tan A+tan B : 1-tan A tan B
= 5/12 + 24/7 : 1-5/12.24/7
= 35/84 + 288/84 : 1- 120/84
=323/84 : 84/84-120/84
=323/84 : -36/84
=-323/36

maaf kalo salah, semoga membantu

TriGonoMetRi

sin A = 5/13
cos A = √(1 - sin² A) = 12/13

cos B = 7/25
sin B = √(1 - cos² B) = 24/25

tan A = sin A/cos A = 5/12
tan B = 24/7

tan (A + B)
= (tan A + tan B) / (1 - tan A tan B)
= (5/12 + 24/7) / (1 - 10/7)
= (5/12 + 24/7) × (-7/3)
= -35/36 - 8
= -8 35/36 ✔