Tentukan persamaan garis yg //dgn garis 2y+6x=9 melalui(-3,-1) | dgn garis 5x-10y+6=0melalui (4,3) -
Matematika
vetrikpangondian
Pertanyaan
Tentukan persamaan garis yg
//dgn garis 2y+6x=9 melalui(-3,-1)
| dgn garis 5x-10y+6=0melalui (4,3)
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//dgn garis 2y+6x=9 melalui(-3,-1)
| dgn garis 5x-10y+6=0melalui (4,3)
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1 Jawaban
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1. Jawaban fatimah3085
2y + 6x = 9
2y = - 6x + 9
y = - 3x + 9/2
m1 = - 3
sejajar = m1 = m2 = - 3
y + 1 = - 3(x + 3)
y = - 3x - 9 - 1
y = - 3x - 10
5x - 10y + 6 = 0
- 10y = - 5x - 6
y = 5/10 x + 6/10
m1 = 5/10
tegak lurus = m1 . m2 = - 1
m2 = - 1 รท 5/10 = - 2
y - 3 = - 2(x - 4)
y = - 2x + 8 + 3
y = - 2x + 11