Matematika

Pertanyaan

mtk. plisss dibantu pakai cara yaaa
mtk.  plisss dibantu pakai cara yaaa

1 Jawaban

  • 5) 4x^2 - mx + 25 = 0
    D = 0
    b^2 - 4ac = 0
    (-m)^2 - 4(25)(4) = 0
    m^2 = 400
    m = +- √400
    m = +- 20
    m = 20 atau m = -20
    utk m= 20
    4x^2 - 20x + 25 = 0
    X1 + X2 = -b/a = -(-20)/4 = 5 ★
    utk m = -20
    4x^2 + 20x + 25 = 0
    X1 + X2 = -20/4 = -5 ★
    Jawaban C

    6) x^2 + (2p-3)x + 2p-19 = 0
    X1 + X2 = 0
    -b/a = 0
    -(2p-3) = 0
    -2p + 3 = 0
    p = 3/2
    X1 . X2 = c/a = 2p-19 = 2(3/2)-19 = 3 - 19 = -16 ★
    Jawaban D

    7) x^2 + 4x + (p-4) = 0
    X1 : X2 = 1 : 3
    X1 = 1/3 X2
    X1 + X2 = -b/a = -4/1 = -4
    1/3 X2 + X2= -4
    4/3 X2 = -4
    X2 = -3 ★
    X1 = 1/3 X2 = 1/3 (-3) = -1 ★
    X1 . X2 = p-4
    (-1)(-3) = p - 4
    3 = p - 4
    p = 3 + 4 = 7 ★
    Jawaban E

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