bantu jawab no.7-9 ya gais. makasih ya gais.

7][
Volume prisma
= luas alas × t
= 1/2 × d² × t
= 1/2 × 10² × 12
= 600 cm³

Volume dluar prisma
= V tabung - V prisma
= πr²t - 600
= 3,14 × 5² × 12 - 600
= 314 × 3 - 600
= 942 - 600
= 342 cm³

9][
Volume kawat
= luas penampang × panjang kawat
= πr² × 200 × 100
= π(5/20)² × 200 × 100
= 314 × 1/8 × 100
= 3925 cm³

Berat kawat
= 3925 × 9
= 35325 gram
= 35,325 kg

jawab
(7)
d tabung =10
r tabung = 5

d tabung  = panjang diagonal persegi
10 = s√2 
s = 10/√2 = 5√2
panjang rusuk  persegi  = s = 5√2

t tabung = s = 5√2

V ruang = v tabung - v prisma
V ruang = π r² t  -  s³
V ruang = π(10² )(5√2) - (5√2)³
V ruang = (3,14)  500 √2  - 50√2
VR = 1.570 √2 - 50√2
VR= 1.520√2 cm³

(9)
panjang kawat = t = 200 m= 20.000 cm
d= 5mm = 0,5 cm
r = 0,25  cm
Volume kawat =  π r² t = (3,14)(0,25)² (20.000) = 3.925 cm²
Berat kawat = V x 9 gram = 3.925 x 9 = 35.325 gram