Tolong cariin jwabannya, tolong scepatnya ya

keliling AFH = AF + FH + AH

AH² = AD² + DH² = 8² + 6² = 100
AH = √100= 10

AF² = AB² + BF² = 15² + 6² = 225 + 36 = 261
AF = √261 = 3√29

FH² = GF² + EF² = 15²+8² = 225 + 64 = 289
FH = √289 = 17

Maka, keliling AFH= 10 + 3√29 + 17 = 27 + 3√29