tolong di jawab ya besok dikumpul

[tex] (27^{2})^{-\frac{1}{3}} = ((3)^{3})^{2})^{-\frac{1}{3}} = (3^{6})^{-\frac{1}{3}} = 3^{-2} = \frac{1}{3^{2}} = \frac{1}{9}[/tex]