Matematika

Pertanyaan

8x-4y=4
2x+3y-21=0
Cari dengan cara subtitusi dan eliminasi

2 Jawaban

  • ◆ Eleminasi
    8x - 4y = 4 | x1
    2x + 3y = 21 | x4

    8x - 4y = 4
    8x + 12 y = 84
    -----------------------( - )
    - 16y = - 80

    y = [tex] \frac{80}{16} [/tex]

    y = 5

    ◆ Substitusi
    8x - 4y = 4

    8x - (4 x 5) = 4

    8x - 20 = 4

    8x = 4 - 20

    8x = - 16

    x = [tex] \frac{-16}{8} [/tex]

    x = - 2
  • substitusi

    8x-4y =4 ---> 2x-y = 1 ---> 2x = y+1

    2x + 3y =21
    (y+1) + 3y = 21
    4y =20
    y = 5

    2x = y + 1
    2x = 5 + 1
    2x = 6
    x = 3

    eliminasi

    2x-y = 1
    2x+3y = 21
    ---------------- -
    -4y = -20
    y = 5

    2x - 5 = 1
    2x = 6
    x = 3

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