30 derajat Reamur berapa derajat Fahrenheit

F = 9/4 × 30 + (32)
= 270/120 + 32
= 2,25 + 32
= 34,25

semoga membantu

=(9/4×30)+32
=67,5+32
=99,5
=99,5°f
#maaf kalo slah semoga membantu