Matematika

Pertanyaan

Yang bisa bantu darurat
1 sampai 4
Yang bisa bantu darurat 1 sampai 4

2 Jawaban

  • 1.) a = 4a^3, b = 5p^3, c = 10a^4 b^2
  • langsung


    1
    a] 4a^3
    b] 5p^3
    c] 10a^4 b^2

    2
    a] [(2a + 6)(a + 2)]/(a + 2) = 2a + 6
    b] [(3x + 2)(x - 3)]/(x - 3) = 3x + 2
    c] [(3b - 4)(2b + 3)]/(2b + 3) = 3b - 4
    d] [(3m - 8)(6m - 2)]/(6m - 2) = 3m - 8

    3]
    (3x + 5)(x - 6) = 3x^2 - 13x - 30

    4]
    (12x - 36)/12 = [12(x - 3)]/12 = x - 3